2n^2+9n-93=2

Solution for 2n^2+9n-93=2 equation:

2n^2+9n-93=2

We move all terms to the left:

2n^2+9n-93-(2)=0

We add all the numbers together, and all the variables

2n^2+9n-95=0

a = 2; b = 9; c = -95;
Δ = b2-4ac
Δ = 92-4·2·(-95)
Δ = 841
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{841}=29$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-29}{2*2}=\frac{-38}{4}
=-9+1/2
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+29}{2*2}=\frac{20}{4}
=5
$